ERROR

Siamo spiacenti, anche se abbiamo fatto del nostro meglio: si è verificato un errore
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 5 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 5 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 5 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 5 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 5 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 5 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 5 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 5 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Luigi Pirandello 
Chacun sa vérité [EPUB ebook] 

الدعم

«À chacun sa vérité» est une comédie tirée d’une nouvelle, «Mme Frola et M. Ponza, son gendre». Dans la petite ville où M. Ponza vient d’être nommé secrétaire de préfecture, on s’interroge et on cherche à savoir qui dit la vérité: Mme Frola, qui prétend que sa fille, disparue depuis quatre ans, est bien l’actuelle épouse de M. Ponza? ce dernier, qui affirme que Mme Frola est folle de croire cela? qui est donc Mme Ponza? Chacun sa vérité, chacun sa folie…

€3.99
طرق الدفع

عن المؤلف

Luigi Pirandello est un écrivain italien, poète, nouvelliste, romancier et dramaturge, né le 28 juin 1867 à Agrigente en Sicile au lieu-dit « Caos », entre Agrigente et Porto Empedocle, durant une épidémie de choléra, et mort le 10 décembre 1936 à Rome. Son oeuvre a été récompensée du prix Nobel de littérature en 1934.

قم بشراء هذا الكتاب الإلكتروني واحصل على كتاب آخر مجانًا!
لغة فرنسي ● شكل EPUB ● صفحات 90 ● ISBN 9782322405848 ● حجم الملف 0.2 MB ● الناشر Books on Demand ● نشرت 2021 ● الإصدار 1 ● للتحميل 24 الشهور ● دقة EUR ● هوية شخصية 8250885 ● حماية النسخ DRM الاجتماعية

المزيد من الكتب الإلكترونية من نفس المؤلف (المؤلفين) / محرر

24٬463 كتب إلكترونية في هذه الفئة