ERROR

Lo sentimos, aunque hicimos todo lo posible: ocurrió un error
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Bloomsbury Publishing 
Children’s Writers’ & Artists’ Yearbook 2025 [PDF ebook] 
The best advice on writing and publishing for children

समर्थन

Foreword by Alice Oseman, creator of the million-copy bestselling Heartstopper books.’This is not a book, it is a sky filled with possibility, so let its wisdom lift you and soar!’ Joseph Coelho, Children’s Laureate Celebrating its 21st edition, this indispensable Children’s Writers’ & Artists’ Yearbook provides everything you need to know to get your work noticed. With thousands of up-to-date contacts and inspiring articles from dozens of successful writers, illustrators and industry insiders, it is the ultimate resource on writing and publishing for children of all ages.Packed with insights and practical tips, it provides expert advice on: – submitting to agents and publishers – writing non-fiction and fiction across genres and formats – poetry, plays, broadcast media and illustration – self-publishing – copyright, finances and contracts – marketing, prizes and festivals – and much, much more …New content in this edition include articles on Your Author Brand by Tom Palmer, Getting Published by Hannah Gold, Writing with empathy by Camilla Chester, What an indie bookshop can offer authors by Carrie & Tim Morris.’Between the covers of this book is everything you need to know to get published.’ Julia Donaldson

€26.63
भुगतान की विधि
यह ईबुक खरीदें और 1 और मुफ़्त पाएं!
भाषा अंग्रेज़ी ● स्वरूप PDF ● पेज 464 ● ISBN 9781399411790 ● प्रकाशक Bloomsbury Publishing ● प्रकाशित 2024 ● डाउनलोड करने योग्य 3 बार ● मुद्रा EUR ● आईडी 9921510 ● कॉपी सुरक्षा Adobe DRM
एक DRM सक्षम ईबुक रीडर की आवश्यकता है

एक ही लेखक से अधिक ईबुक / संपादक

53,515 इस श्रेणी में ईबुक