ERROR

Maalesef, elimizden gelenin en iyisini yaptığımız halde: bir hata oluştu
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 12 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 12 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 12 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 12 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 12 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 12 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 12 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 12 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Галина Романова 
Ничто не вечно под луной [EPUB ebook] 

Supporto

Судьба давно отвернула свой прекрасный лик от Али. Началось все два года назад, когда ее мужа посадили за зверское убийство. Аля не может ему простить не столько само преступление, сколько измену. Она одинока и зла. А тут еще шеф и друг Иван загремел с инфарктом, и на фирме, которую она временно возглавила, начались неприятности. Срываются поставки продукции клиентам. Может дело в конкурентах? Аля приглашает шефа их фирмы к себе. Но ужин не состоялся. Аля нашла его труп на территории своего особняка. У ментов она на подозрении, а брат убитого поклялся ей отомстить. Но это только горькая прелюдия к посыпавшимся на Алю бедам…

€3.99
Modalità di pagamento
Acquista questo ebook e ricevine 1 in più GRATIS!
Lingua Russo ● Formato EPUB ● Pagine 320 ● ISBN 9785041278663 ● Dimensione 1.7 MB ● Età 17-16 anni ● Casa editrice ЭКСМО ● Città Moscow ● Paese RU ● Pubblicato 2024 ● Scaricabile 24 mesi ● Moneta EUR ● ID 6605191 ● Protezione dalla copia DRM sociale

Altri ebook dello stesso autore / Editore

120.757 Ebook in questa categoria