ERROR

เราต้องขออภัย - แม้ว่าเราจะพยายามอย่างดีที่สุด: เกิดข้อผิดพลาด
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Mark Griffiths 
Challenge of Existential Social Work Practice [EPUB ebook] 

Support

Social work is being constantly shaped by external forces such as new information technology, managerialism, increased public accountability and programme risk management. Although an appreciation of how these forces impact on direct service is required, an exclusive focus on them can prevent social workers from genuinely embracing current practice opportunities. Existentialism – a philosophy that emphasises our existence in the world as free and responsible agents helping to shape our own experiences through the choices we make – has influenced the development of social work almost from its origins. This ground-breaking text highlights social work’s existential heritage and the existential threats and challenges to current social work practice, and explores how existential philosophy can help direct service social workers find purpose and meaning in their daily practice in a radically uncertain and alienated twenty first century world. This is a fascinating read from one of the leading scholars in existentialist social work, and an essential guide for today’s student and practitioner in the application of existential social work practice.

€38.23
payment methods
Buy this ebook and get 1 more FREE!
Language English ● Format EPUB ● ISBN 9781137528308 ● Publisher Macmillan Education UK ● Published 2017 ● Downloadable 3 times ● Currency EUR ● ID 6676900 ● Copy protection Adobe DRM
Requires a DRM capable ebook reader

More ebooks from the same author(s) / Editor

128,769 Ebooks in this category