ERROR

We are sorry - although we did our best: an error occurred
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 2 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 2 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 2 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 2 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 2 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 2 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 2 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 2 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

SIGMUND FREUD 
PSYCHOPATHOLOGY OF EVERYDAY LIFE [EPUB ebook] 

Wsparcie

’Psychopathology of Everyday Life’ by Sigmund Freud
About: In this work, Freud explores how seemingly trivial and minor errors (like slips of the tongue, forgetfulness, and mistakes) can reveal deeper unconscious thoughts and desires, laying the foundation for psychoanalytic theory.

€0.99
Metody Płatności
Kup ten ebook, a 1 kolejny otrzymasz GRATIS!
Język Angielski ● Format EPUB ● Strony 284 ● ISBN 9789361911699 ● Rozmiar pliku 0.5 MB ● Wydawca Swan Books ● Opublikowany 2023 ● Do pobrania 24 miesięcy ● Waluta EUR ● ID 10227018 ● Ochrona przed kopiowaniem Adobe DRM
Wymaga czytnika ebooków obsługującego DRM

Więcej książek elektronicznych tego samego autora (ów) / Redaktor

787 266 Ebooki w tej kategorii