ERROR

हमें खेद है - हालाँकि हमने अपना सर्वश्रेष्ठ किया: एक त्रुटि हुई
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 9 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 9 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 9 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 9 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 9 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 9 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 9 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 9 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Geoff Thompson 
Introducing Functional Grammar [EPUB ebook] 

Apoio

Introducing Functional Grammar, third edition, provides a user-friendly overview of the theoretical and practical aspects of the systemic functional grammar (SFG) model.No prior knowledge of formal linguistics is required as the book provides: An opening chapter on the purpose of linguistic analysis, which outlines the differences between the two major approaches to grammar – functional and formal. An overview of the SFG model – what it is and how it works. Advice and practice on identifying elements of language structure such as clauses and clause constituents. Numerous examples of text analysis using the categories introduced, and discussion about what the analysis shows. Exercises to test comprehension, along with answers for guidance. The third edition is updated throughout, and is based closely on the fourth edition of Halliday and Matthiessen’s Introduction to Functional Grammar. A glossary of terms, more exercises and an additional chapter are available on the product page at: https://www.routledge.com/9781444152678.Introducing Functional Grammar remains the essential entry guide to Hallidayan functional grammar, for undergraduate and postgraduate students of language and linguistics.

€48.64
Métodos de Pagamento
Compre este e-book e ganhe mais 1 GRÁTIS!
Língua Inglês ● Formato EPUB ● Páginas 328 ● ISBN 9781135983208 ● Editora Taylor and Francis ● Publicado 2013 ● Carregável 6 vezes ● Moeda EUR ● ID 2718440 ● Proteção contra cópia Adobe DRM
Requer um leitor de ebook capaz de DRM

Mais ebooks do mesmo autor(es) / Editor

53.515 Ebooks nesta categoria