ERROR

We are sorry - although we did our best: an error occurred
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 2 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 2 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 2 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 2 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 2 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 2 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 2 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 2 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Jake Arnott 
House of Rumour [EPUB ebook] 

Apoio

Larry Zagorski spins wild tales of fantasy worlds for pulp magazines. But as the Second World War hangs in the balance, the lines between imagination and reality are starting to blur. In London, spymasters enlist occultists in the war of propaganda. In Southern California, a charismatic rocket scientist summons dark forces and an SF writer founds a new religion. In Munich, Nazis consult astrologists as they plot peace with the West and dominion over the East. And a conspiracy is born that will ripple through the decades to come. The truth, it seems, is stranger than anything Larry could invent. But when he looks back on the 20th century, the past is as uncertain as the future. Just where does truth end and illusion begin? THE HOUSE OF RUMOUR is a novel of soaring ambition, a mind-expanding journey through the ideas that have put man on the moon yet brought us to the brink of self-destruction. What will you believe?

€3.99
Métodos de Pagamento
Compre este e-book e ganhe mais 1 GRÁTIS!
Língua Inglês ● Formato EPUB ● ISBN 9781848945067 ● Editora Hodder & Stoughton ● Publicado 2012 ● Carregável 6 vezes ● Moeda EUR ● ID 2758793 ● Proteção contra cópia Adobe DRM
Requer um leitor de ebook capaz de DRM

Mais ebooks do mesmo autor(es) / Editor

298.072 Ebooks nesta categoria