ERROR

Lo sentimos, aunque hicimos todo lo posible: ocurrió un error
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Autor: Jana von Bergner

Apoio
Das Magazin “der selfpublisher” erscheint im Uschtrin Verlag, dem Fachverlag für Autorinnen und Autoren. Die Zeitschrift wendet sich an Autoren, die ihre Werke selbst veröffentlichen (wollen), sowie an Hybridautoren, also an Autoren, deren Werke in Verlagen erscheinen. Herausgeber des selfpublishers ist der Selfpublisher-Verband e.V.




3 Ebooks por Jana von Bergner

Jasmin Zipperling & Daniel Seebacher: der selfpublisher 13, 1-2019, Heft 13, März 2019
‘der selfpublisher’ – Deutschlands 1. Selfpublishing-Magazin Selfpublisher sind immer auf der Suche. Nach neuen Lesern. Nach Infos, wie sie ihre Bücher noch attraktiver machen. Und nach Dienstleister …
PDF
Alemão
€4.99
Susanne Pavlovic & Cally Stronk: der selfpublisher 14, 2-2019, Heft 14, Juni 2019
‘der selfpublisher’ – Deutschlands 1. Selfpublishing-Magazin Selfpublisher sind immer auf der Suche. Nach neuen Lesern. Nach Infos, wie sie ihre Bücher noch attraktiver machen. Und nach Dienstleister …
PDF
Alemão
€4.99
Maike Burk & Tom Oberbichler: der selfpublisher 16, 4-2019, Heft 16, Dezember 2019
‘der selfpublisher’ – Deutschlands 1. Selfpublishing-Magazin Selfpublisher sind immer auf der Suche. Nach neuen Lesern. Nach Infos, wie sie ihre Bücher noch attraktiver machen. Und nach Dienstleister …
PDF
Alemão
€4.99