ERROR

เราต้องขออภัย - แม้ว่าเราจะพยายามอย่างดีที่สุด: เกิดข้อผิดพลาด
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Marcel Danesi 
Practice Makes Perfect: Complete Italian Grammar, Premium Fourth Edition [EPUB ebook] 

Apoio

All the practice and instruction you need to communicate effectively in Italian-now with an enhanced app featuring text-to-speech!If you are a beginner to intermediate Italian language learner, getting a handle on grammar is your key to communicating correctly and effectively. In Practice Makes Perfect: Complete Italian Grammar, you’ll find tons of practice and everything else you need instruction, clear explanations, and comparisons to English grammar to build your knowledge and communicate more effectively in Italian.Based on the successful approach of the Practice Makes Perfect series, Complete Italian Grammar, Premium Fourth Edition covers all aspects of Italian grammar you’ll need to master, from all the key verb tenses to noun, adjective, pronoun, and preposition usage. Crystal-clear explanations, realistic examples and extensive array of engaging exercises help you focus your efforts on the practical aspects of communicating in Italian.With an additional boost from the high-frequency vocabulary used throughout the book and an answer key for reference and quick feedback, Practice Makes Perfect: Complete Italian Grammar is the best, most indispensable workbook to help you upgrade your command of the language.

€28.31
Métodos de Pagamento
Compre este e-book e ganhe mais 1 GRÁTIS!
Língua Inglês ● Formato EPUB ● Páginas 360 ● ISBN 9781266017896 ● Editora McGraw Hill LLC ● Publicado 2023 ● Carregável 3 vezes ● Moeda EUR ● ID 9289035 ● Proteção contra cópia Adobe DRM
Requer um leitor de ebook capaz de DRM

Mais ebooks do mesmo autor(es) / Editor

53.515 Ebooks nesta categoria