ERROR

Мы сожалеем - хотя мы сделали все возможное: произошла ошибка
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 8 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 8 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 8 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 8 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 8 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 8 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 8 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 8 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Mike Gandon 
English for International Journalists [PDF ebook] 

Apoio

English for International Journalists is a clear and engaging step-by-step guide for non-native speakers using English in journalism across all forms of media. In-depth language analysis is provided in the specialised context of journalism, as well as a comprehensive approach to the rules and guidelines necessary for avoiding the pitfalls and errors that undermine accuracy and clarity. The book, written by Mike Gandon and edited by Heather Purdey, covers a broad range of vital subjects, including:* Making contact* Interviewing* Grammar and journalistic writing* Sensitive issues* The language of argument* The language of impartial and accurate reporting* Bloggers and broadcasters* Reporting economy, health and the environment.The book is closely supported by online resources concentrating on the spoken word, intonation and pronunciation, and also features an expansive range of exercises and tests, suitable for self-study or to be set as coursework. English for International Journalists presents readers with the essential tools for producing journalism in English today.

€50.29
Métodos de Pagamento
Compre este e-book e ganhe mais 1 GRÁTIS!
Língua Inglês ● Formato PDF ● Páginas 200 ● ISBN 9781136500848 ● Editor Heather Purdey ● Editora Taylor and Francis ● Publicado 2013 ● Carregável 6 vezes ● Moeda EUR ● ID 2648137 ● Proteção contra cópia Adobe DRM
Requer um leitor de ebook capaz de DRM

Mais ebooks do mesmo autor(es) / Editor

53.515 Ebooks nesta categoria