ERROR

Przepraszamy - choć zrobiliśmy wszystko, co w naszej mocy: wystąpił błąd
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 7 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 7 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 7 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 7 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 7 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 7 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 7 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 7 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Edgar Allan Poe 
Ligeia (Fantasy and Horror Classics) [EPUB ebook] 

поддержка

This book contains Edgar Allen Poe’s 1838 short story, "Ligeia". An anonymous narrator recounts the story of his meeting a beautiful and intellectual woman "in some large, old decaying city near the Rhine." They get married, and Ligeia introduces her husband to all manner of mathematical and metaphysical knowledge. Soon after, she becomes seriously ill and dies. The narrator’s second marriage comes to a similarly tragic end, resulting in the uncanny reappearance of the mysterious Ligeia. A gripping and atmospheric tale, "Ligeia" is highly recommended for fans of fantasy and horror fiction, and would make for a fantastic addition to any collection. Edgar Allan Poe (1809-1849) was an American author, editor, poet, and critic. Most famous for his stories of mystery and horror, he was one of the first American short story writers, and is widely considered to be the inventor of the detective fiction genre. Many antiquarian books such as this are becoming increasingly rare and expensive. We are republishing "Ligeia" now in an affordable, high-quality edition complete with a specially commissioned new biography of the author.

€6.44
Способы оплаты
Купите эту электронную книгу и получите еще одну БЕСПЛАТНО!
язык английский ● Формат EPUB ● страницы 26 ● ISBN 9781447499541 ● издатель Read Books Ltd. ● опубликованный 2012 ● Загружаемые 6 раз ● валюта EUR ● Код товара 2710474 ● Защита от копирования Adobe DRM
Требуется устройство для чтения электронных книг с поддержкой DRM

Больше книг от того же автора (ов) / редактор

20 953 Электронные книги в этой категории