ERROR

Нам шкода - хоча ми зробили все можливе: сталася помилка
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

автор: Patrick J. Sweeney

поддержка
Patrick J. Sweeney II heads ODIN Technologies, an RFID integration and software development company. He learned the technology at MIT and is considered an industry expert.




3 Электронные книги Patrick J. Sweeney

Patrick J. Sweeney: RFID For Dummies
* Many companies have asked suppliers to begin using RFID (radio frequency identification) tags by 2006 * RFID allows pallets and products to be scanned at a greater distance and with less effort tha …
PDF
английский
DRM
€19.99
Patrick J. Sweeney: RFID For Dummies
* Many companies have asked suppliers to begin using RFID (radio frequency identification) tags by 2006 * RFID allows pallets and products to be scanned at a greater distance and with less effort tha …
EPUB
английский
DRM
€19.99
Patrick J. Sweeney & Julie Frost: Paddy Picks a Puppy
Paddy Picks a Puppy — A Heartwarming Adventure in Personality Embark on an enchanting journey with Paddy as he navigates the delightful world of puppies, learning profound life lessons along the way. …
EPUB
английский
DRM
€10.99