ERROR

我们很抱歉 - 尽管我们做到了最好:发生了错误
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Jieun Kiaer 
Pragmatic Syntax [PDF ebook] 

สนับสนุน

Jieun Kiaer puts forward an argument in this book that the grammar of a language directly underpins the processing of the language, in real time. This is a view that runs against the orthodoxy of linguistic theorizing for the last 50 years, which has insisted that languages have to be characterized in terms that make little or no reference to the dynamics of language use.This orthodox view fails to fit languages in which the verb has to be at the end of the clause – which encompasses more than half of the world’s languages. Thus, as this book shows, these languages remain very problematic for conventional theories. Using a mixture of corpus methods, sentence structure analysis, prosody and psycholinguistic theory, Kiaer redresses this imbalance. The data features both Korean and English example and it functions as one of the very first general introductions to Dynamic Syntax available.

€43.96
วิธีการชำระเงิน
ซื้อ eBook เล่มนี้และรับฟรีอีก 1 เล่ม!
ภาษา อังกฤษ ● รูป PDF ● หน้า 256 ● ISBN 9781623561147 ● สำนักพิมพ์ Bloomsbury Publishing ● การตีพิมพ์ 2014 ● ที่สามารถดาวน์โหลดได้ 3 ครั้ง ● เงินตรา EUR ● ID 3408723 ● ป้องกันการคัดลอก Adobe DRM
ต้องใช้เครื่องอ่านหนังสืออิเล็กทรอนิกส์ที่มีความสามารถ DRM

หนังสืออิเล็กทรอนิกส์เพิ่มเติมจากผู้แต่งคนเดียวกัน / บรรณาธิการ

53,515 หนังสืออิเล็กทรอนิกส์ในหมวดหมู่นี้