ERROR

Lo sentimos, aunque hicimos todo lo posible: ocurrió un error
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 3 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 3 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

ผู้เขียน: Vesa Kaihlavirta

สนับสนุน

3 หนังสืออิเล็กทรอนิกส์โดย Vesa Kaihlavirta

ปกของ Paul Johnson & Vesa Kaihlavirta: Learning Rust
Paul Johnson & Vesa Kaihlavirta: Learning Rust
Start building fast and robust applications with the power of Rust by your side About This Book
  • Get started with the language to build scalable and high performance applications
  • Thi …
EPUB
อังกฤษ
DRM
€41.99
ปกของ Rahul Sharma & Vesa Kaihlavirta: Mastering Rust
Rahul Sharma & Vesa Kaihlavirta: Mastering Rust
Become proficient in designing, developing and deploying effective software systems using the advanced constructs of Rust Key Features
  • Improve your productivity using the latest version of R …
EPUB
อังกฤษ
€46.44
ปกของ Rahul Sharma & Vesa Kaihlavirta: The Complete Rust Programming Reference Guide
Rahul Sharma & Vesa Kaihlavirta: The Complete Rust Programming Reference Guide
Design and implement professional-level programs by leveraging modern data structures and algorithms in Rust Key Features: Improve your productivity by writing more simple and easy code in Rust Disco …
EPUB
อังกฤษ
DRM
€43.19