ERROR

我们很抱歉 - 尽管我们做到了最好:发生了错误
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Gunda Windmüller 
Weiblich, ledig, glücklich – sucht nicht [EPUB ebook] 
Eine Streitschrift

Destek

Über die Kunst, glücklich single zu sein – ein Debattenbuch mit hohem Identifikationspotential. Gunda Windmüller plädiert leidenschaftlich dafür, unser Bild von der bemitleidenswerten Singlefrau zu überdenken. Und sie macht Mut: Denn das Leben allein kann verdammt gut sein. Leider nimmt das den meisten Frauen ohne festen Partner nach wie vor kaum einer ab. «Was macht die Liebe? Hast du schon mal Online-Dating probiert?» Das ist gut gemeint, es schwingt aber immer mit: Was stimmt nicht mit dir? Die wichtigere Frage lautet jedoch: Was stimmt nicht mit einer Gesellschaft, in der allen Scheidungsstatistiken zum Trotz die dauerhafte Paarbeziehung nach wie vor als Nonplusultra gilt?

€9.99
Ödeme metodları

Yazar hakkında

Gunda Windmüller, geboren 1980, ist promovierte Literaturwissenschaftlerin und hat als Journalistin für u.a. Zeit Online und Welt kmpkt geschrieben. Gemeinsam mit Katja Berlin hostete und produzierte sie den Podcast «Fix&Vierzig». Ihr erstes Sachbuch «Weiblich, ledig, glücklich – sucht nicht» erschien 2019 bei Rowohlt. Sie hat eine Ausbildung zur Yogalehrerin abgeschlossen und unterrichtet seit Herbst 2021 Yoga in Berlin.

Bu e-kitabı satın alın ve 1 tane daha ÜCRETSİZ kazanın!
Dil Almanca ● Biçim EPUB ● Sayfalar 288 ● ISBN 9783644405424 ● Dosya boyutu 8.2 MB ● Yayımcı Rowohlt E-Book ● Kent Hamburg ● Ülke DE ● Yayınlanan 2019 ● Baskı 1 ● İndirilebilir 24 aylar ● Döviz EUR ● Kimlik 6724382E-Book Endkundennutzungsbedinungen des Verlages ● Kopya koruma Sosyal DRM

Aynı yazardan daha fazla e-kitap / Editör

5.250 Bu kategorideki e-kitaplar