ERROR

Нам шкода - хоча ми зробили все можливе: сталася помилка
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

F.A. Hayek 
Constitution of Liberty [EPUB ebook] 
The Definitive Edition

Підтримка

Originally published in 1960, The Constitution of Liberty delineates and defends the principles of a free society and traces the origin, rise, and decline of the rule of law. Casting a skeptical eye on the growth of the welfare state, Hayek examines the challenges to freedom posed by an ever expanding government as well as its corrosive effect on the creation, preservation, and utilization of knowledge. In distinction to those who confidently call for the state to play a greater role in society, Hayek puts forward a nuanced argument for prudence. Guided by this quality, he elegantly demonstrates that a free market system in a democratic polity-under the rule of law and with strong constitutional protections of individual rights-represents the best chance for the continuing existence of liberty. Striking a balance between skepticism and hope, Hayek’s profound insights remain strikingly vital half a century on. This definitive edition of The Constitution of Liberty will give a new generation the opportunity to learn from Hayek’s enduring wisdom.

€51.52
методи оплати
Придбайте цю електронну книгу та отримайте ще 1 БЕЗКОШТОВНО!
Мова Англійська ● Формат EPUB ● Сторінки 600 ● ISBN 9780429637971 ● Редактор Ronald Hamowy ● Видавець Taylor and Francis ● Опубліковано 2020 ● Завантажувані 3 разів ● Валюта EUR ● Посвідчення особи 7974759 ● Захист від копіювання Adobe DRM
Потрібен читач електронних книг, що підтримує DRM

Більше електронних книг того самого автора / Редактор

49 310 Електронні книги в цій категорі