ERROR

Нам шкода - хоча ми зробили все можливе: сталася помилка
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Anthony Walsh 
Criminological Theory [EPUB ebook] 
Assessing Philosophical Assumptions

Ủng hộ

Criminologists can benefit from questioning the underlying assumptions upon which they rest their work. Philosophy has the ability to clarify our thoughts, inform us of why we think about things the way we do, solve contradictions in our thinking we never knew existed, and even dissolve some dichotomies we thought were cast in stone. One of those dichotomies is free will vs. determinism. Criminology must reckon with both free will and agency, as posited by some theories, and determinism, as posited by others-including the ever more influential fields of genetics and biosocial criminology. Criminological Theory: Assessing Philosophical Assumptions examines philosophical concepts such as these in the context of important criminological theories or issues that are foundational but not generally considered in the literature on this topic. The uniqueness of this treatment of criminological theory is that rather than reporting what this person or that has said about a particular theory, Walsh exposes the philosophical assumptions underlying the theory. Students and scholars learn to clarify their own biases and better analyze the implications of a broad range of theories of crime and justice.

€92.24
phương thức thanh toán
Mua cuốn sách điện tử này và nhận thêm 1 cuốn MIỄN PHÍ!
Ngôn ngữ Anh ● định dạng EPUB ● Trang 238 ● ISBN 9781317523086 ● Nhà xuất bản Taylor and Francis ● Được phát hành 2014 ● Có thể tải xuống 3 lần ● Tiền tệ EUR ● TÔI 3386904 ● Sao chép bảo vệ Adobe DRM
Yêu cầu trình đọc ebook có khả năng DRM

Thêm sách điện tử từ cùng một tác giả / Biên tập viên

128.769 Ebooks trong thể loại này