ERROR

เราต้องขออภัย - แม้ว่าเราจะพยายามอย่างดีที่สุด: เกิดข้อผิดพลาด
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 16 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 16 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Jennifer Taylor 
Wife For Real [EPUB ebook] 

Ủng hộ

Did she dare become his wife for real?Katherine’s marriage seems perfect. Her husband, Jordan, is handsome, charming and wealthy-and their home idyllic. However, in reality, theirs is a marriage of convenience. Katherine has been happy to accept this-it’s easy, comfortable and suits her needs. Now, one year into their arrangement, Katherine’s peace of mind is shattered when Jordan demands that they be married in every sense.Dare Katherine agree? After all, it is not as if she hasn’t wanted Jordan in ever sense. She simply has to face her memories of their wedding night and come to terms with her own all too "real" needs.

€2.31
phương thức thanh toán
Mua cuốn sách điện tử này và nhận thêm 1 cuốn MIỄN PHÍ!
Ngôn ngữ Anh ● định dạng EPUB ● ISBN 9781472067562 ● Nhà xuất bản HarperCollins Publishers ● Được phát hành 2013 ● Có thể tải xuống 6 lần ● Tiền tệ EUR ● TÔI 2842291 ● Sao chép bảo vệ Adobe DRM
Yêu cầu trình đọc ebook có khả năng DRM

Thêm sách điện tử từ cùng một tác giả / Biên tập viên

297.222 Ebooks trong thể loại này