ERROR

Lamentamos, embora tenhamos feito o melhor possível: ocorreu um erro
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 6 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 6 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 6 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 6 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 6 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 6 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 6 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 6 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

John Taylor 
Latin Beyond GCSE [EPUB ebook] 

Ủng hộ

Latin Beyond GCSE covers all the linguistic requirements for the OCR AS and A Level in Latin. It aims to bring students to a point where they can tackle original Latin texts with confidence. Although designed as a continuation of Latin to GCSE, it is self-contained and can be used independently. This new edition is brought in line with the new OCR specifications and benefits from a completely redesigned layout, with added colour and images. The answer key is available on a companion website. The first part of the book introduces new constructions and the translation of sentences from English to Latin, with reading passages at AS standard. The next sections provide translation and comprehension passages at AS and A-level, including verse unseens, scansion, and a list of 300 common poetic words. Next come longer unadapted extracts from a range of authors. Finally there is a reference section including a summary of all constructions, a comprehensive grammar, and a general vocabulary of about 1200 Latin words.

€22.02
phương thức thanh toán
Mua cuốn sách điện tử này và nhận thêm 1 cuốn MIỄN PHÍ!
Ngôn ngữ Anh ● định dạng EPUB ● Trang 368 ● ISBN 9781474299886 ● Nhà xuất bản Bloomsbury Publishing ● Được phát hành 2017 ● Có thể tải xuống 3 lần ● Tiền tệ EUR ● TÔI 5031230 ● Sao chép bảo vệ Adobe DRM
Yêu cầu trình đọc ebook có khả năng DRM

Thêm sách điện tử từ cùng một tác giả / Biên tập viên

12.281 Ebooks trong thể loại này