ERROR

Нам шкода - хоча ми зробили все можливе: сталася помилка
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 10 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 10 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

作者: Committee on Cost of and Payment for Animal Research

支持

2 电子书 Committee on Cost of and Payment for Animal Research

Committee on Cost of and Payment for Animal Research & Institute for Laboratory Animal Research: Strategies That Influence Cost Containment in Animal Research Facilities
Care and use of animals in research are expensive, prompting efforts to contain or reduce costs. Components of those costs are personnel, regulatory compliance, veterinary medical care, and laborator …
EPUB
英语
DRM
€52.95
Committee on Cost of and Payment for Animal Research & Institute for Laboratory Animal Research: Strategies That Influence Cost Containment in Animal Research Facilities
Care and use of animals in research are expensive, prompting efforts to contain or reduce costs. Components of those costs are personnel, regulatory compliance, veterinary medical care, and laborator …
PDF
英语
DRM
€41.85