ERROR

我们很抱歉 - 尽管我们做到了最好:发生了错误
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Luigi Pirandello 
Seis Personajes en busca de autor [EPUB ebook] 

支持

Luis Pirandello, ganador en 1934 del Premio Nobel de Literatura, es uno de los más famosos dramaturgos de Europa. ‘Seis Personajes en busca de autor’, una historia que evoca en particular la relación entre la locura y la percepción de la realidad, es considerada por algunos como su obra maestra.

€1.49
支付方式
购买此电子书可免费获赠一本!
语言 西班牙语 ● 格式 EPUB ● ISBN 9782366686807 ● 文件大小 0.1 MB ● 出版者 FV Éditions ● 发布时间 2015 ● 下载 24 个月 ● 货币 EUR ● ID 5072775 ● 复制保护

来自同一作者的更多电子书 / 编辑

36,201 此类电子书