ERROR

Kami ingin memohon maaf - walaupun kami melakukan yang terbaik: Ralat berlaku
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 19 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 19 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 19 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 19 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 19 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 19 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 19 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 19 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Jane Griffiths 
John Skelton and Poetic Authority [PDF ebook] 
Defining the Liberty to Speak

Support

John Skelton and Poetic Authority is the first book-length study of Skelton for almost twenty years, and the first to trace the roots of his poetic theory to his practice as a writer and translator. It demonstrates that much of what has been found challenging in his work may be attributed to his attempt to reconcile existing views of the poet’s role in society with discoveries about the writing process itself. The result is a highly idiosyncratic poeticsthat locates the poet’s authority decisively within his own person, yet at the same time predicates his ‘liberty to speak’ upon the existence of an engaged, imaginative audience. Skelton is frequently treated as a maverick, but this book places his theory and practice firmly in the context of later sixteenth aswell as fifteenth-century traditions. Focusing on his relations with both past and present readers, it reassess his place in the English literary canon.

€59.72
payment methods
Buy this ebook and get 1 more FREE!
Language English ● Format PDF ● ISBN 9780191515194 ● Publisher Clarendon Press ● Published 2006 ● Downloadable 6 times ● Currency EUR ● ID 2272211 ● Copy protection Adobe DRM
Requires a DRM capable ebook reader

More ebooks from the same author(s) / Editor

67,668 Ebooks in this category