ERROR

我们很抱歉 - 尽管我们做到了最好:发生了错误
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 13 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 13 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Fulton J. Sheen 
Life of Christ [EPUB ebook] 

Apoio

Originally published in 1958, ‘Life of Christ’ was written by Fulton J. Sheen, an American bishop of the Catholic Church known for his preaching and especially his work on television and radio. It is widely proclaimed as a classic work of Christian faith and has been hailed as the most eloquent of Sheen’s many books. The fruit of many years of reflection, prayer, and research, it is a dramatic and moving recounting of the birth, life, Crucifixion, and Resurrection of Christ, and a passionate portrait of the God-Man, the teacher, the healer, and most of all the Savior, whose promise has sustained humanity for two millennia.
With his customary insight and reverence, Sheen interprets the scripture and describes Christ, not only in historical perspective, but also in exciting and contemporary terms, seeing in Christ’s life both modern parallels and timeless lessons. His thoughtful, probing analysis provides new insight into well-known Gospel events.
A captivating blend of philosophy, history, and Biblical exegesis, from the best-known and most-loved American Catholic leader of the twentieth century, it has long been a source of inspiration and guidance. For those seeking to better understand the message of Jesus Christ, this vivid retelling of the greatest story ever lived is a must read.

€0.99
Métodos de Pagamento
Compre este e-book e ganhe mais 1 GRÁTIS!
Língua Inglês ● Formato EPUB ● Páginas 600 ● ISBN 9789389716542 ● Tamanho do arquivo 0.9 MB ● Editora DIGITAL FIRE ● Publicado 2023 ● Edição 1 ● Carregável 24 meses ● Moeda EUR ● ID 8815289 ● Proteção contra cópia Adobe DRM
Requer um leitor de ebook capaz de DRM

Mais ebooks do mesmo autor(es) / Editor

141.045 Ebooks nesta categoria