ERROR

हमें खेद है - हालाँकि हमने अपना सर्वश्रेष्ठ किया: एक त्रुटि हुई
Typedatabase
MessageYou have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near "AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categorie..." at line 5
QuerySELECT (SELECT categories_id FROM categories_description WHERE language_id = 9 AND categories_id = 000) AS cat1, (SELECT categories_id FROM categories_description WHERE language_id = 9 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2, (SELECT categories_id FROM categories_description WHERE language_id = 9 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3, (SELECT categories_id FROM categories_description WHERE language_id = 9 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4, (SELECT categories_name FROM categories_description WHERE language_id = 9 AND categories_id = 000) AS cat1name, (SELECT categories_name FROM categories_description WHERE language_id = 9 AND categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2name, (SELECT categories_name FROM categories_description WHERE language_id = 9 AND categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3name, (SELECT categories_name FROM categories_description WHERE language_id = 9 AND categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4name, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 000) AS cat1url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3url, (SELECT url_text FROM commerce_seo_url_without_language WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4url, (SELECT wod_count_products FROM categories WHERE categories_id = 000) AS cat1cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 00 AND SUBSTRING(categories_id,2,1) != "0") AS cat2cnt, (SELECT wod_count_products FROM categories WHERE categories_id = 0 AND SUBSTRING(categories_id,3,1) != "0") AS cat3cnt, (SELECT wod_count_products FROM categories WHERE categories_id = AND SUBSTRING(categories_id,4,1) != "0") AS cat4cnt

Jared C. Wilson 
Friendship with the Friend of Sinners [EPUB ebook] 
The Remarkable Possibility of Closeness with Christ

Підтримка

The Bible calls Jesus the friend of sinners, but it’s hard to imagine what friendship with Jesus really looks like. We so often don’t even know how to do friendship with the people around us, despite all the options we have to connect. So how are we supposed to feel that close to a holy, perfect, and invisible God? How do we see Jesus as the real person he is? And how do we experience true friendship with him when we struggle to maintain true friendship on earth?Join author Jared C. Wilson as he explores what it means to be a friend of Jesus. Through candid personal stories and insights into the Gospels, Wilson uncovers easily overlooked details of the close relationship Jesus had with his followers. He reveals the ways we often hold Jesus at arm’s length and shows how to draw close to him through radical honesty, consistent communication, and unconditional love.If you’ve found yourself lonely and longing for connection and friendship, it’s time to discover the remarkable possibility of closeness with Christ.

€11.71
методи оплати
Придбайте цю електронну книгу та отримайте ще 1 БЕЗКОШТОВНО!
Мова Англійська ● Формат EPUB ● Сторінки 224 ● ISBN 9781493441143 ● Видавець Baker Publishing Group ● Опубліковано 2023 ● Завантажувані 3 разів ● Валюта EUR ● Посвідчення особи 9092700 ● Захист від копіювання Adobe DRM
Потрібен читач електронних книг, що підтримує DRM

Більше електронних книг того самого автора / Редактор

76 938 Електронні книги в цій категорі